Question

Say I have a function like below, how do I capture the output of the Process.spawn call? I should also be able to kill the process if it takes longer than a specified timeout.

Note that the function must also be cross-platform (Windows/Linux).

def execute_with_timeout!(command)
  begin
    pid = Process.spawn(command)     # How do I capture output of this process?
    status = Timeout::timeout(5) {
      Process.wait(pid)
    }
  rescue Timeout::Error
    Process.kill('KILL', pid)
  end
end

Thanks.

Answer 1

You can use IO.pipe and tell Process.spawn to use the redirected output without the need of external gem.

Of course, only starting with Ruby 1.9.2 (and I personally recommend 1.9.3)

The following is a simple implementation used by Spinach BDD internally to capture both out and err outputs:

# stdout, stderr pipes
rout, wout = IO.pipe
rerr, werr = IO.pipe

pid = Process.spawn(command, :out => wout, :err => werr)
_, status = Process.wait2(pid)

# close write ends so we could read them
wout.close
werr.close

@stdout = rout.readlines.join("\n")
@stderr = rerr.readlines.join("\n")

# dispose the read ends of the pipes
rout.close
rerr.close

@last_exit_status = status.exitstatus

The original source is in features/support/filesystem.rb

Is highly recommended you read Ruby’s own Process.spawn documentation.

Hope this helps.

PS: I left the timeout implementation as homework for you 😉