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Home/ Questions/Q 7686343
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T19:27:28+00:00 2026-05-31T19:27:28+00:00

Say I have a function that takes an arbitrary number of arguments (the last

  • 0

Say I have a function that takes an arbitrary number of arguments (the last is callback):

xxx.create ('arg1', 'arg2', ..., 'arg10', callback) {
    ...
}

But it’s ugly. I want to be able to extract the first few parameters and do something like:

var args = ['arg1', 'arg2', ..., 'arg10']
xxx.create (args.explode(), callback) {
    ...
}

Of course I can write a wrapper for xxx.create(), but I want it to be clean.

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T19:27:30+00:00Added an answer on May 31, 2026 at 7:27 pm

    You’re looking for Function.apply.

    var args = ['arg1', 'arg2', ..., 'argN'];
    xxx.create.apply(xxx, args.concat(callback)) {
        // ...
    }
    

    I used Array.concat so as to not mutate the original args array. If that’s not a problem, either of these will suffice:

    var args = ['arg1', 'arg2', ..., 'argN', callback];
    xxx.create.apply(xxx, args) {
        // ...
    }
    
    // or
    
    var args = ['arg1', 'arg2', ..., 'argN'];
    args.push(callback);
    xxx.create.apply(xxx, args) {
        // ...
    }
    

    Now, if you wanted to use a wrapper instead of exposing the Function.apply call:

    function create_wrapper() {
        xxx.create(xxx, arguments);
    }
    
    // then
    
    create_wrapper('arg1', 'arg2', ..., 'argN', callback);
    

    will do the job.

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