Question

Say I have a function that returns an array like this…

array(
    0 => 'jpg',
    1 => 400,
    2 => 500
);

I want the indexes 1 and 2 only, and I want them as local variables. I don’t care about 0.

I could do…

list($throwaway, $width, $height) = getImageDetails($imagePath);
unset($throwaway);

…but obviously that is very ugly.

I tried placing NULL there, but I got the scope resolution error.

Is there a clean way to skip an array index using PHP’s list()?

Answer 1

Yep, don’t populate that argument, this is perfectly valid:

list(, $width, $height) = getImageDetails($imagePath);

(see also Example 1 in the manual)