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Home/ Questions/Q 910859
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T17:06:30+00:00 2026-05-15T17:06:30+00:00

Say I have a namedtuple like this: FooTuple = namedtuple(FooTuple, item1, item2) And I

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Say I have a namedtuple like this:

FooTuple = namedtuple("FooTuple", "item1, item2")

And I want the following function to be used for hashing:

foo_hash(self):
    return hash(self.item1) * (self.item2)

I want this because I want the order of item1 and item2 to be irrelevant (I will do the same for the comparison-operator). I thought of two ways to do this. The first would be:

FooTuple.__hash__ = foo_hash

This works, but it feels hacked. So I tried subclassing FooTuple:

class EnhancedFooTuple(FooTuple):
    def __init__(self, item1, item2):
        FooTuple.__init__(self, item1, item2)

    # custom hash function here

But then I get this:

DeprecationWarning: object.__init__() takes no parameters

So, what can I do? Or is this a bad idea altogether and I should just write my own class from scratch?

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  1. Editorial Team
    Editorial Team
    2026-05-15T17:06:30+00:00Added an answer on May 15, 2026 at 5:06 pm

    I think there is something wrong with your code (my guess is that you created an instance of the tuple with the same name, so fooTuple is now a tuple, not a tuple class), because subclassing the named tuple like that should work. Anyway, you don’t need to redefine the constructor. You can just add the hash function:

    In [1]: from collections import namedtuple
    
    In [2]: Foo = namedtuple('Foo', ['item1', 'item2'], verbose=False)
    
    In [3]: class ExtendedFoo(Foo):
       ...:     def __hash__(self):
       ...:         return hash(self.item1) * hash(self.item2)
       ...: 
    
    In [4]: foo = ExtendedFoo(1, 2)
    
    In [5]: hash(foo)
    Out[5]: 2
    
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