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Home/ Questions/Q 9246627
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T09:32:09+00:00 2026-06-18T09:32:09+00:00

Say I have a namespace args that I obtain from calling parser.parse_args() , which

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Say I have a namespace args that I obtain from calling parser.parse_args(), which parses the command line arguments.

How can I import all variables from this namespace to my current namespace?

e.g.

parser.add_argument('-p', '--some_parameter', default=1)

args = parser.parse_args()

# ... code to load all variables defined in the namespace args ...

print some_parameter

I could certainly do:

some_parameter = args.some_parameter

but if I have a large number of parameters I would need one such line for each parameter.

Is there another way of importing variables from a namespace without having to go through them one by one?

PS: from args import * does not work.

PS2: I am aware that this is a bad practice, but this can help in some corner cases, such us when prototyping code and tests very quickly.

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  1. Editorial Team
    Editorial Team
    2026-06-18T09:32:10+00:00Added an answer on June 18, 2026 at 9:32 am

    Update your local namespace with the result of the vars() function:

    globals().update(vars(args))
    

    This is generally not that great an idea; leave those attributes in the namespace instead.

    You could create more problems than you solved with this approach, especially if you accidentally configure arguments with a dest name that shadows a built-in or local you care about, such as list or print or something. Have fun hunting down that bug!

    Tim Peters already stated this in his Zen of Python:

    Namespaces are one honking great idea — let’s do more of those!

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