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Home/ Questions/Q 8203879
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T07:42:42+00:00 2026-06-07T07:42:42+00:00

Say I have a simple forum model: class User(models.Model): username = models.CharField(max_length=25) … class

  • 0

Say I have a simple forum model:

class User(models.Model):
    username = models.CharField(max_length=25)
    ...

class Topic(models.Model):
    user = models.ForeignKey(User)
    ...

class Post(models.Model):
    user = models.ForeignKey(User)
    ...

Now say I want to see how many topics and posts each users of subset of users has (e.g. their username starts with “ab”).

So if I do one query for each post and topic:

User.objects.filter(username_startswith="ab")
            .annotate(posts=Count('post'))
            .values_list("username","posts")

Yeilds:

[('abe', 5),('abby', 12),...]

and

User.objects.filter(username_startswith="ab")
            .annotate(topics=Count('topic'))
            .values_list("username","topics")

Yields:

[('abe', 2),('abby', 6),...]

HOWEVER, when I try annotating both to get one list, I get something strange:

User.objects.filter(username_startswith="ab")
            .annotate(posts=Count('post'))
            .annotate(topics=Count('topic'))
            .values_list("username","posts", "topics")

Yields:

[('abe', 10, 10),('abby', 72, 72),...]

Why are the topics and posts multiplied together? I expected this:

[('abe', 5, 2),('abby', 12, 6),...]

What would be the best way of getting the correct list?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T07:42:43+00:00Added an answer on June 7, 2026 at 7:42 am

    I think Count('topics', distinct=True) should do the right thing. That will use COUNT(DISTINCT topic.id) instead of COUNT(topic.id) to avoid duplicates.

    User.objects.filter(
        username_startswith="ab").annotate(
        posts=Count('post', distinct=True)).annotate(
        topics=Count('topic', distinct=True)).values_list(
        "username","posts", "topics")
    
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