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Home/ Questions/Q 7575361
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T16:40:10+00:00 2026-05-30T16:40:10+00:00

Say I have a simple function that alerts a message: function callMessage(msg){ alert(msg); }

  • 0

Say I have a simple function that alerts a message:

function callMessage(msg){
        alert(msg);
    }

Now when I call it like so, it does not work. Throws error “hey is not defined”

function sayHi(){
        var hey = "hi there"
        setTimeout("callMessage(hey)", 1000);
    }
    sayHi();

But when I call it inside an anonymous function it does work:

function sayHi(){
        var hey = "hi there"
        setTimeout(function(){callMessage(hey);}, 1000);
    }
    sayHi();

Why is the “hey” variable only visible when I put it inside an anonymous function?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T16:40:11+00:00Added an answer on May 30, 2026 at 4:40 pm

    In the first example, the code is evaluated after the timer expired and the current scope was left. hey is undefined at that moment.

    The second example – the proper way to use setTimeout – uses an anonymous function created when invoking setTimeout(). This anonymous function also receives a copy of the current scope.

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