Question

Say I have an interface that specifies two void methods with no parameters. How can I “plug” two System.Action(T) methods in some class that implements the interface? In my example below, this would be in the void PushFoo(Action bar1, Action bar2) method:

public interface IFoo
{
    void Bar1();
    void Bar2();
}

public class Bla
{
    Stack<IFoo> _fooStack = new Stack<IFoo>();

    public void PushFoo(IFoo foo)
    {
        _fooStack.Push(foo);
    }

    public void PushFoo(Action bar1, Action bar2)
    {
        IFoo foo = null;

        // assign bar1 and bar2 to foo
        //foo = ... ;

        _fooStack.Push(foo);
    }
}

Answer 1

public Class ActionableFoo : IFoo
{
    Action _bar1, _bar2;

    public ActionableFoo(Action b1, Action b2)
    {
        _bar1 = b1;
        _bar2 = b2;
    }

    public void Bar1() { if(_bar1 != null) _bar1(); }
    public void Bar2() { if(_bar2 != null) _bar2(); }
}

Then , in your example:

public void PushFoo(Action bar1, Action bar2)
{
    IFoo foo = new ActionableFoo(bar1, bar2);
    _fooStack.Push(foo);
}