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Home/ Questions/Q 3786432
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T11:40:56+00:00 2026-05-19T11:40:56+00:00

Say I have the Django model class: class Foo(models.Model): bar = models.CharField() baz =

  • 0

Say I have the Django model class:

class Foo(models.Model):
 bar = models.CharField()
 baz = models.CharField()

and the ModelAdmins:

class Foo_Admin_1(admin.ModelAdmin):
 list_display = ['id','bar']

class Foo_Admin_2(admin.ModelAdmin):
 list_display = ['id','baz']

is there any way to register both ModelAdmins so that they show up under the Django Admin interface?

I tried:

admin.site.register(Foo,Foo_Admin_1)
admin.site.register(Foo,Foo_Admin_2)

but I get the error:

The model Foo is already registered

Any suggestions?

If not, are there alternative ways to (dynamically) control the fields shown in the ModelAdmin change list view?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T11:40:56+00:00Added an answer on May 19, 2026 at 11:40 am

    Create an empty proxy subclass and register it instead:

    class Foo(models.Model):
        bar = models.CharField()
        baz = models.CharField()
    
    # admin.py
    class FooProxy(Foo):
        class Meta:
            proxy=True
    
    admin.site.register(Foo, FooAdmin1)
    admin.site.register(FooProxy, FooAdmin2) 
    
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