Question

Say that I have a function foo defined as

   [a b] = foo(c ).

If I consider a function handle

 f = @(c)foo(c)

to be used e.g. in a cellfun call, what I get is an f behaving equivalently to a foo defined like

  a = foo(c)

i.e., the returned value b gets lost.

Therefore, when such an f is put in a cellfun call, the output cell will have just the as and will miss the bs (which I currently care about). Visually

    cellfun(f,input)

  [a(input{1})]           ?
  [a(input{2})]           ?
     ....            b gets killed along the way

---

Question: how to define a function handle to foo which catches just the bs? i.e. giving a behavior analogous to a definition of foo like

  b = foo(c)

i.e.^2, wasting the as.

Moreover, is it possible to (efficiently) catch both a and b in a unique cellfun call?

Answer 1

From the documentation of cellfun:

[A1,…,Am] = cellfun(func,C1,…,Cn) calls the function specified by function handle func and passes elements from cell arrays C1,…,Cn, where n is the number of inputs to function func. Output arrays A1,…,Am, where m is the number of outputs from function func, contain the combined outputs from the function calls.

So yes, cellfun can use a multi-output function and in this case it simply returns a number of outputs. If you want to use the second one only, you can use ~ to ignore the first one. The same goes for multiple outputs of anonymous functions – they will be returned if you specify multiple output arguments. Here is a simple code:

function test
    x{1} = 1;
    x{2} = 2;
    [~, B] = cellfun(@foo, x);
    f=@(c)foo(c);
    [A, B] = f(1);

    function [a b] = foo(x)
        a = x+1;
        b = x+2;
    end
end