Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6573621
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T15:09:24+00:00 2026-05-25T15:09:24+00:00

Scanner scanner = new Scanner(); int number = 1; do { try { option

  • 0
Scanner scanner = new Scanner();
int number = 1;

do
{
    try
    {
        option = scanner.nextInt();
    }
    catch (InputMismatchException exception)
    {
        System.out.println("Integers only, please.");
    }
}
while (number != 0);

Despite the exception handling, this code will enter an infinite loop when non-integer input is given. Instead of Scanner pausing to collect input in the next iteration, it simply continues throwing InputMismatchExceptions until the program is killed.

What’s the best way to scan for integer (or another type, I suppose) input, discarding invalid input and continuing the loop normally?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T15:09:24+00:00Added an answer on May 25, 2026 at 3:09 pm

    You should check whether or not the input can be parsed as an int before attempting to assign the input’s value to an int. You should not be using an exception to determine whether or not the input is correct it is bad practice and should be avoided.

    if(scanner.hasNextInt()){
       option = scanner.nextInt();
    }else{
       System.out.printLn("your message");
    }
    

    This way you can check whether or not the input can be interpreted as an int and if so assign the value and if not display a message. Calling that method does not advance the scanner.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

System.out.println(Please enter the required word :); Scanner scan2 = new Scanner(System.in); String word2 =
// Calculating term frequency System.out.println(Please enter the required word :); Scanner scan = new
Scanner s = null; try { s = new Scanner(new BufferedReader(new FileReader(rates.txt))); for (int
If I have the following Java code: int[][] readAPuzzle() { Scanner input = new
public static void main (String args[]) { Scanner myinput=new Scanner(System.in) ; //Arrary length comes
this code is correct?? String note = text.txt; FileWriter file = new FileWriter(note); Scanner
So, I'm getting stuck with this piece of code: import java.util.InputMismatchException; import java.util.Scanner; public
//Count the number of documents available File folder = new File(C:\\Users\\user\\fypworkspace\\TextRenderer); File[] listOfFiles =
// Calculating term frequency int filename = 11; String[] fileName = new String[filename]; int
I'm using scanner to read a text file line by line but then how

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.