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Home/ Questions/Q 8404981
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T22:44:05+00:00 2026-06-09T22:44:05+00:00

Screenshot: I populated the above menu in screenshot using below code, but silly me

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Screenshot:

enter image description here

I populated the above menu in screenshot using below code, but silly me I can’t figure out how can I create click event on each subitem since they don’t have property name? :S My intention is to click, let say, “Do and Do”, then the file will be opened using Process.Start(filename);. Please bear with me as I am very new to programming. 😐 Thank you so much!

private void loadViewTemplates(string path)
{
    foreach (string file in Directory.GetFiles(path, "*.txt"))
    {
        ToolStripItem subItem = new ToolStripMenuItem();
        subItem.Text = Path.GetFileNameWithoutExtension(file);
        viewTemplatesToolStripMenuItem.DropDownItems.Add(subItem);
    }
}
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  1. Editorial Team
    Editorial Team
    2026-06-09T22:44:07+00:00Added an answer on June 9, 2026 at 10:44 pm

    Try stubbing out the click procedure. The sender would be the menu item that was clicked:

    private void MenuClicked(object sender, EventArgs e) {
      MessageBox.Show("Clicked on " + ((ToolStripMenuItem)sender).Text);
    }
    

    Then wire up the click event for each menu:

    ToolStripItem subItem = new ToolStripMenuItem();
    subItem.Click += MenuClicked;
    subItem.Text = Path.GetFileNameWithoutExtension(file);
    viewTemplatesToolStripMenuItem.DropDownItems.Add(subItem);
    
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