Question

SELECT * 
FROM afspraken
WHERE user_id =  '2'
AND datum >  '2012-06-05'
OR (
user_id =  '2'
AND datum =  '2012-06-05'
AND begintijd >=  '22:47'
)
ORDER BY datum DESC , begintijd ASC 

This above is my query.. And while i should get zero result i still get one which is:

id  user_id     datum      begintijd    opmerking
114 2         2012-06-05    9:30        Deze afspraak is online gemaakt.

Now if i have this correctly, this query has 2 options to give results.. which is:
The user_id must be the same AND the date has to be higher then 2012-06-05.. Since its the same date this won’t give the result..

Now the second option which is when the user_id is the same, the date is the same and when the beginningtime is the same or higher.. Now the time in the query shown is 22:47.. The time in the database is 9:30 morning.. How is 9:30 morning higher or equal to 22:47??

    id  int(10)                             
    user_id int(10) 
    datum   date    
    begintijd   varchar(5)
    opmerking   varchar(8000)
    reminder    int(10)

Answer 1

The idea would be to cast your time columns and values to Time:

SELECT CAST('20:05' AS Time) > CAST('9:06' AS Time) #returns 1 (compares times - what you want)

SELECT '20:05' > '9:06' #returns 0 (compares strings - not what you want)

Read more here.