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Home/ Questions/Q 6728435
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:10:11+00:00 2026-05-26T10:10:11+00:00

SELECT Y/X as Z FROM ( SELECT (count(county) FROM `cleanup_site_list_2011` WHERE county=’kings’) as X,

  • 0
SELECT Y/X as Z
FROM (
    SELECT
    (count(county) FROM `cleanup_site_list_2011` WHERE county='kings') as X,
    (count(county) FROM `cleanup_site_list_2011` WHERE county='kings' AND people != 0) as Y
    FROM `cleanup_site_list_2011`
) as innertable

In the above example the two “SELECT …” represent nested queries of any description (X and Y will be integers). When I try to use this statement I get the error

#1054 - Unknown column 'Y' in 'field list'

How would I get MySQL to recognize the names of the columns I created? Also, once the math works out, how would I make the division result in a float? Or does it do this automatically?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:10:11+00:00Added an answer on May 26, 2026 at 10:10 am

    One way to deal with this is to give the columns their ‘custom names’ in a subquery, then use those custom names in the surrounding query:

    SELECT 
      Y/X as Z -- moved to outer query
    FROM (
      SELECT 
        (...) as X, -- assign custom names in subquery
        (...) as Y, 
      FROM `table`
    ) as innertable;
    

    For the second question:

    mysql> select 4 / 3;
    +--------+
    | 4 / 3  |
    +--------+
    | 1.3333 |
    +--------+
    1 row in set (0.00 sec)
    

    Does that answer it? (MySQL 5)

    More information here.

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