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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T16:46:34+00:00 2026-06-02T16:46:34+00:00

shifters… I’ve to do something, that twist my mind. I’m getting a hex value

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shifters…

I’ve to do something, that twist my mind.

I’m getting a hex value as String (for example: “AFFE”) and have to decide, if bit 5 of Byte one is set.

public boolean isBitSet(String hexValue) {
    //enter your code here
    return "no idea".equals("no idea")
}

Any hints?

Regards,

Boskop

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  1. Editorial Team
    Editorial Team
    2026-06-02T16:46:37+00:00Added an answer on June 2, 2026 at 4:46 pm

    The simplest way is to convert String to int, and use bit arithmetic:

    public boolean isBitSet(String hexValue, int bitNumber) {
        int val = Integer.valueOf(hexValue, 16);
        return (val & (1 << bitNumber)) != 0;
    }               ^     ^--- int value with only the target bit set to one
                    |--------- bit-wise "AND"
    
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