Question

Similar to this question but with objects instead of pointers.

If I have the following code

Foo f;
vector<Foo> vect;
vect.push_back(f);
vect.erase(vect.begin());

Where does my object go? Is delete called on it? What if someone else holds a pointer to it? Is this a memory leak?

Answer 1

push_back stores a copy of f in the vector, and erase destroys it. f itself is not affected by that.

All pointers, references and iterators to an element in a vector are invalidated when you erase it. Using them to access the element after erase yields undefined behavior.