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Home/ Questions/Q 104605
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Asked: May 11, 20262026-05-11T01:18:29+00:00 2026-05-11T01:18:29+00:00

Simply put, I have a table with, among other things, a column for timestamps.

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Simply put, I have a table with, among other things, a column for timestamps. I want to get the row with the most recent (i.e. greatest value) timestamp. Currently I’m doing this:

SELECT * FROM table ORDER BY timestamp DESC LIMIT 1 

But I’d much rather do something like this:

SELECT * FROM table WHERE timestamp=max(timestamp) 

However, SQLite rejects this query:

SQL error: misuse of aggregate function max() 

The documentation confirms this behavior (bottom of page):

Aggregate functions may only be used in a SELECT statement.

My question is: is it possible to write a query to get the row with the greatest timestamp without ordering the select and limiting the number of returned rows to 1? This seems like it should be possible, but I guess my SQL-fu isn’t up to snuff.

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  1. 2026-05-11T01:18:29+00:00Added an answer on May 11, 2026 at 1:18 am
    SELECT * from foo where timestamp = (select max(timestamp) from foo) 

    or, if SQLite insists on treating subselects as sets,

    SELECT * from foo where timestamp in (select max(timestamp) from foo) 
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