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Home/ Questions/Q 6544011
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T11:24:55+00:00 2026-05-25T11:24:55+00:00

So, given the following: #include <stdio.h> int * getarr(); int main(int argc, char* argv)

  • 0

So, given the following:

#include <stdio.h>
int * getarr();
int main(int argc, char* argv)
{
    int * arr = getarr();
    printf("%d", sizeof(arr));
}

int* getarr()
{
    static int a[4] = {0,1,0,3};
    return a;
}

How does one find the length of arr? arr[4] == 0, but so does arr[0] and arr[2].

If this were a char*, the answer would be iterate until '\0', but that does not seem to work here as '\0' == 0.

Addressing arr[5] can seems to consistently result in a value > 163 – 1 (the size of an int on my system), but that does not seem to be a reliable measure as it strikes me as simply an empty location in memory.

Is there a way to retrieve this value consistently? Or does it simply have to be passed in?

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  1. Editorial Team
    Editorial Team
    2026-05-25T11:24:55+00:00Added an answer on May 25, 2026 at 11:24 am

    You cannot retreive the length of the array when you are in the main() function. This information has been lost when the int[4] was converted to an int * returned by getarr()

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