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Home/ Questions/Q 584475
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:54:06+00:00 2026-05-13T14:54:06+00:00

So, I have the following code: def LSCPHandler.send_message(message, hostname, port) s = TCPSocket.open(hostname, port)

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So, I have the following code:

  def LSCPHandler.send_message(message, hostname, port)
s = TCPSocket.open(hostname, port)
s.print message
ret = s.recv(1024)
s.close 
LSCPHandler.parse_error(ret)
return ret  

end

Which works just fine, normally. The server I’m talking to returns the response pretty quickly, usually, and all is well.

Then, today, something went wrong with the server. Not my problem, BUT, this resulted in my entire application hanging, waiting for recv to time out. This isn’t exactly optimal.

Is there a way to time out recv if I dont’ hear something back immediately? I tried looking at the ruby documentation, but it really confuses me(i.e. TCPSocket only implements three methods, none of them open or recv, and it’s parent class of Socket doesn’t implemente these methods either. And Socket’s parent class appears to be Object? I’m throughly confused)

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:54:06+00:00Added an answer on May 13, 2026 at 2:54 pm

    You can set the receive timeout socket options on the socket to something else than the default. The tricky bit is to pick a suitable number that still works in all use cases, i.e. you don’t want your recv call to timeout too early.

    s.setsockopt(Socket::SOL_SOCKET, Socket::SO_RCVTIMEO, <timeout>)
    
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