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Home/ Questions/Q 444751
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T21:18:07+00:00 2026-05-12T21:18:07+00:00

So I have this big, hairy if/else statement. I pass a tracking number to

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So I have this big, hairy if/else statement. I pass a tracking number to it, and then it determines what type of tracking number it is.

How can I simplify this thing? Specifically wanting to reduce the number of lines of codes.

if num_length < 8
  tracking_service = false
else
  if number[1, 1] == 'Z'
    tracking_service = 'ups'
  elsif number[0, 1] == 'Q'
    tracking_service = 'dhl'
  elsif number[0, 2] == '96' && num_length == 22
    tracking_service = 'fedex'
  elsif number[0, 1] == 'H' && num_length == 11
    tracking_service = 'ups'
  elsif number[0, 1] == 'K' && num_length == 11
    tracking_service = 'ups'
  elsif num_length == 18 || num_length == 20
    check_response(number)
  else
    case num_length
    when 17
      tracking_service = 'dhlgm'
    when 13,20,22,30
      tracking_service = 'usps'
    when 12,15,19
      tracking_service = 'fedex'
    when 10,11
      tracking_service = 'dhl'
    else
      tracking_service = false  
    end  
  end
end

Yes, I know. It’s nasty.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T21:18:07+00:00Added an answer on May 12, 2026 at 9:18 pm

    Try this. I rewrote it using case and regular expressions. I also used :symbols instead of "strings" for the return values, but you can change that back.

    tracking_service = case number
      when /^.Z/ then :ups
      when /^Q/ then :dhl
      when /^96.{20}$/ then :fedex
      when /^[HK].{10}$/ then :ups
    else
      check_response(number) if num_length == 18 || num_length == 20
      case num_length
        when 17 then :dhlgm
        when 13, 20, 22, 30 then :usps
        when 12, 15, 19 then :fedex
        when 10, 11 then :dhl
        else false
      end
    end
    
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