Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 123381
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 11, 20262026-05-11T04:16:39+00:00 2026-05-11T04:16:39+00:00

So lets say I have this interface: public interface IBox { public void setSize(int

  • 0

So lets say I have this interface:

public interface IBox {    public void setSize(int size);    public int getSize();    public int getArea();   //...and so on } 

And I have a class that implements it:

public class Rectangle implements IBox {    private int size;    //Methods here } 

If I wanted to use the interface IBox, i can’t actually create an instance of it, in the way:

public static void main(String args[]) {     Ibox myBox=new Ibox(); } 

right? So I’d actually have to do this:

public static void main(String args[]) {     Rectangle myBox=new Rectangle(); } 

If that’s true, then the only purpose of interfaces is to make sure that the class which implements an interface has got the correct methods in it as described by an interface? Or is there any other use of interfaces?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. 2026-05-11T04:16:40+00:00Added an answer on May 11, 2026 at 4:16 am

    Interfaces are a way to make your code more flexible. What you do is this:

    Ibox myBox=new Rectangle(); 

    Then, later, if you decide you want to use a different kind of box (maybe there’s another library, with a better kind of box), you switch your code to:

    Ibox myBox=new OtherKindOfBox(); 

    Once you get used to it, you’ll find it’s a great (actually essential) way to work.

    Another reason is, for example, if you want to create a list of boxes and perform some operation on each one, but you want the list to contain different kinds of boxes. On each box you could do:

    myBox.close() 

    (assuming IBox has a close() method) even though the actual class of myBox changes depending on which box you’re at in the iteration.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 190k
  • Answers 190k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer To change the prompt function at any time, just execute… May 12, 2026 at 5:54 pm
  • Editorial Team
    Editorial Team added an answer You should use matcher.find() instead. May 12, 2026 at 5:54 pm
  • Editorial Team
    Editorial Team added an answer I wrote a jQuery plugin to do this a while… May 12, 2026 at 5:54 pm

Related Questions

Let's say I have an interface representing a domain object: public interface IFoo {
Let's say I have a WCF contract such as [ServiceContract] public interface IContract {
I need advice on how to return a limited set of data from an
In C++, is it possible to have a base plus derived class implement a

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.