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Home/ Questions/Q 7404077
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:12:13+00:00 2026-05-29T05:12:13+00:00

So this is the code I have: $(‘.showvideo’).click(function(){ // removes ‘show’ class from all

  • 0

So this is the code I have:

$('.showvideo').click(function(){ // removes 'show' class from all images that aren't 'vid'
    showAll();
    if($('.gallery li img').hasClass('video')){
        $('.gallery li img').addClass('show').removeClass('hide');
    }
    else{
        $('.gallery li img').addClass('hide').removeClass('show');
    }
});

At the moment it adds the class ‘show’ to all the images within ‘container’, even though only two out of the six have the class ‘video’. How do I only add the class ‘show’ to only those images which have the class ‘video’?

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:12:14+00:00Added an answer on May 29, 2026 at 5:12 am

    You can add the video class to your individual selector to get just the items you want like this. Assuming the video class is on the img tag itself, it would work like this:

    $('.showvideo').click(function(){ // removes 'show' class from all images that aren't 'vid'
        showAll();
        $('.gallery li img.video').addClass('show').removeClass('hide');
        $('.gallery li img').not('.video').addClass('hide').removeClass('show');
    });
    

    Or, a little more efficiently:

    $('.showvideo').click(function(){ // removes 'show' class from all images that aren't 'vid'
        showAll();
        var $items = $('.gallery li img');
        $items.filter('.video').addClass('show').removeClass('hide');
        $items.not('.video').addClass('hide').removeClass('show');
    });
    
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