Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
String a="A";
String b="B";
final String c="C";
final String d="D";
String e=a+b;
String f=a+b;
System.out.println(e==f);//false
String g=c+d;
String h=c+d;
System.out.println(g==h);//true
Why it is so? String objects are created in a special memory are called string constant pool. But here what is the significance of final variable.
The compiler sees that c and d are final. This means that the compiler knows that c and d will never change. It thus compiles the code to
g and h are thus two references to the same STring literal, which is interned.
He can’t optimize e and f the same way, because a and b are not final and can thus change.