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Home/ Questions/Q 6617887
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T20:45:29+00:00 2026-05-25T20:45:29+00:00

struct Example { char* string; int x; }; When I allocate a new instance

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struct Example
{
     char* string;
     int x;
};

When I allocate a new instance of Example 8 bytes are allocated (assuming that sizeof(char*)=4). So when I call this:

Example* sp = new Example();
sp->string = "some text";

How is the string allocated? Is is placed in a random empty memory location? or is there some kind of relation between sp and member string?

So, “some text” makes a dynamic memory allocation?

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  1. Editorial Team
    Editorial Team
    2026-05-25T20:45:29+00:00Added an answer on May 25, 2026 at 8:45 pm

    String literals like that are put wherever the compiler wants to put them, they have a static storage duration (they last for the life of the entire program), and they never move around in memory.

    The compiler usually stores them in the executable file itself in a read-only portion of memory, so when you do something = "some text"; it just makes something point to that location in memory.

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