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Home/ Questions/Q 8449325
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T10:40:19+00:00 2026-06-10T10:40:19+00:00

Suppose I have an IF condition : if (A || B) ∧ | |

  • 0

Suppose I have an IF condition :

if (A || B) 
    ∧
    |
    |
   left
{ 
   // do something  
}

Now suppose that A is more likely to receive a true value then B , why do I care which one is on the left ?

If I put both of them in the IF brackets , then I know (as the programmer of the code) that both parties are needed .

The thing is , that my professor wrote on his lecture notes that I should put the “more likely variable to receive a true” on the left .

Can someone please explain the benefit ? okay , I put it on the left … what am I gaining ? run time ?

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  1. Editorial Team
    Editorial Team
    2026-06-10T10:40:21+00:00Added an answer on June 10, 2026 at 10:40 am

    Its not just about choosing the most likely condition on the left. You can also have a safe guard on the left meaning you can only have one order. Consider

    if (s == null || s.length() == 0) // if the String is null or empty.
    

    You can’t swap the order here as the first condition protects the second from throwing an NPE.

    Similarly you can have

    if (s != null && s.length() > 0) // if the String is not empty
    

    The reason for choosing the most likely to be true for || or false for && is a micro-optimisation, to avoid the cost of evaluated in the second expression. Whether this translates to a measurable performance difference is debatable.

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