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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T06:24:43+00:00 2026-05-15T06:24:43+00:00

Suppose I have any long hash, like a 16 bytes MD5 or a 20

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Suppose I have any “long” hash, like a 16 bytes MD5 or a 20 bytes SHA1.
I want to reduce this hash to fit on 4 bytes, for GetHashCode() purposes.

First, I’m perfectly aware that I’ll get more collisions. That’s totally fine in my case, but I’d still prefer to get the less possible collisions.

There are several solutions to my problem:

  • I could take the 4 first bytes of the hash.
  • I could take the 4 last bytes of the hash.
  • I could take 4 random bytes of the hash.
  • I could generate a hash of the hash, involving classic prime numbers multiplications.

Are there other solutons I didn’t think about? And more importantly, what method will give me the most unique hash code? I’m currently supposing they’re almost equivalent.

Microsoft chose that the public key token of an assembly is the last 8 bytes of the SHA1 hash of its public key, so I’ll probably go for this solution but I’d like to know why.

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  1. Editorial Team
    Editorial Team
    2026-05-15T06:24:44+00:00Added an answer on May 15, 2026 at 6:24 am

    Any hash is already a reduction.

    Cryptographic hashes are designed so that no part of the data has more influence on any part of the hash than any other. So it doesn’t matter which bits of the hash you pick.

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