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Home/ Questions/Q 6529175
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T09:36:19+00:00 2026-05-25T09:36:19+00:00

Suppose I have the following interface: public interface Interface<T extends Number>{ public Vector<Interface<T>> getVector();

  • 0

Suppose I have the following interface:

public interface Interface<T extends Number>{
    public Vector<Interface<T>> getVector();
}

and the following class implementing that interface:

public abstract class C<T extends Number> implements Interface<T>{

    private Vector<C<T>> vector;
    public Vector<Interface<T>> getVector(){ //errror
         return this.vector;
    }
} 

Why is not legal returning a Vector<C<T>> meanwhile is legal ( obviously) returning a Vector<Interface<T>>. C is actually implementing Interface, so it should be possible, right? What am I missing?

EDIT:

why this work for non generics interface? Is this actually a generic related problem?

public interface Interface{
        public Interface getVector();
    }

public abstract class C implements Interface {

    private C;
    public Interface getVector(){ //errror
         return this.c;
    }
} 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T09:36:20+00:00Added an answer on May 25, 2026 at 9:36 am

    Because the Vector is explicitly made up of Interface<T>, not things that extend Interface<T>, I believe this would work if you changed the definition to

     public Vector<? extends Interface<T>> getVector();
    

    The problem is that for some V implements T or V extends T that Foo<V> is not a supertype of Foo<T>. The compiler does not test inheritance on the generic arguments unless you explicitly indicate that extension point.

    Using Vector<? extends Interface<T>> means “allow any class that implements or extends Interface<T>, whereas Vector<Interface<T>> means a vector consisting only of Interface<T> items.

    Perhaps it’s more concrete to consider that List<Integer> is not an acceptable replacement for List<Number> despite Integer extending Number for precisely the same reason.

    update:

    I tested this and the following compiles without any errors or warnings

    interface Interface<T extends Number>{
        public Vector<? extends Interface<T>> getVector();
    }
    
    abstract class C<T extends Number> implements Interface<T>{
    
        private Vector<C<T>> vector;
        public Vector<? extends Interface<T>> getVector(){
             return this.vector;
        }
    } 
    
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