Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 785897
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T20:57:09+00:00 2026-05-14T20:57:09+00:00

Suppose you have a Java method void foobar(int id, String … args) and want

  • 0

Suppose you have a Java method

void foobar(int id, String ... args)

and want to pass both String arrays and Strings into the method. Like this

String arr1[]={"adas", "adasda"};
String arr2[]={"adas", "adasda"};
foobar(0, "adsa", "asdas");
foobar(1, arr1);
foobar(2, arr1, arr2);
foobar(3, arr1, "asdas", arr2);

In Python there is “*” for this. Is there some way better than such rather ugly helper method:

static String[] concat(Object... args) {
    List<String> result = new ArrayList<String>();
    for (Object arg : args) {
        if (arg instanceof String) {
            String s = (String) arg;
            result.add(s);
        } else if (arg.getClass().isArray() && arg.getClass().getComponentType().equals(String.class)) {
            String arr[] = (String[]) arg;
            for (String s : arr) {
                result.add(s);
            }
        } else {
            throw new RuntimeException();
        }
    }
    return result.toArray(new String[result.size()]);
}

which allows

foobar(4, concat(arr1, "asdas", arr2));
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T20:57:10+00:00Added an answer on May 14, 2026 at 8:57 pm

    Java doesn’t have any built in syntactic sugar for this, but your helper method could be a lot nicer:

    private static String[] concat(Object... stringOrArrays) {
        List<String> result = new ArrayList<String>();
        for (Object stringOrArray : stringOrArrays) {
            if (stringOrArray instanceof String) {
                result.add((String) stringOrArray);
            } else if (stringOrArray instanceof String[]) {
                Collections.addAll(result, (String[]) stringOrArray);
            } else if (stringOrArray == null) {
                results.add(null)
            } else {
                throw new RuntimeException(stringOrArray + " not a String or String[]");
            }
        }
        return result.toArray(new String[0]);
    }
    

    I could come up with a one liner (to avoid the method) but I don’t recommend it:

        foobar(1, new ArrayList<String>() {{
            addAll(Arrays.asList(arr1));
            addAll(Arrays.asList(arr2));
            add(arr3);
        }}.toArray(new String[0]));
    

    The only advantage the one-liner has is type safety.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 535k
  • Answers 534k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer That should definitely be a method, not a property. A… May 17, 2026 at 12:57 am
  • Editorial Team
    Editorial Team added an answer It is not possible as of now. Possibly because the… May 17, 2026 at 12:57 am
  • Editorial Team
    Editorial Team added an answer $s = 'capture {this} text and exclude \{that} {a} \{b}… May 17, 2026 at 12:57 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Related Questions

Suppose that I have a Java class with a static method, like so: class
Suppose I have these interfaces: public interface I1 { void foo(); } public interface
Good day, masters. Suppose I have a java class A: class A { public
Suppose I have an interface: public interface FooInterface { public void someMethod(); } and
Suppose you have the following situation #include <iostream> class Animal { public: virtual void
Suppose, I have a lot of classes, which are constructed using Java reflection (for
suppose I have the following source table (called S): name gender code Bob 0
According to the documentation : [ java.lang.reflect. ] Proxy provides static methods for creating
I have followed the installation instructions as shown here to install the FedOne server,I
I have an e-commerce package called Prestashop. They allow you to sell virtual products,

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.