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Home/ Questions/Q 785897
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:57:09+00:00 2026-05-14T20:57:09+00:00

Suppose you have a Java method void foobar(int id, String … args) and want

  • 0

Suppose you have a Java method

void foobar(int id, String ... args)

and want to pass both String arrays and Strings into the method. Like this

String arr1[]={"adas", "adasda"};
String arr2[]={"adas", "adasda"};
foobar(0, "adsa", "asdas");
foobar(1, arr1);
foobar(2, arr1, arr2);
foobar(3, arr1, "asdas", arr2);

In Python there is “*” for this. Is there some way better than such rather ugly helper method:

static String[] concat(Object... args) {
    List<String> result = new ArrayList<String>();
    for (Object arg : args) {
        if (arg instanceof String) {
            String s = (String) arg;
            result.add(s);
        } else if (arg.getClass().isArray() && arg.getClass().getComponentType().equals(String.class)) {
            String arr[] = (String[]) arg;
            for (String s : arr) {
                result.add(s);
            }
        } else {
            throw new RuntimeException();
        }
    }
    return result.toArray(new String[result.size()]);
}

which allows

foobar(4, concat(arr1, "asdas", arr2));
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:57:10+00:00Added an answer on May 14, 2026 at 8:57 pm

    Java doesn’t have any built in syntactic sugar for this, but your helper method could be a lot nicer:

    private static String[] concat(Object... stringOrArrays) {
        List<String> result = new ArrayList<String>();
        for (Object stringOrArray : stringOrArrays) {
            if (stringOrArray instanceof String) {
                result.add((String) stringOrArray);
            } else if (stringOrArray instanceof String[]) {
                Collections.addAll(result, (String[]) stringOrArray);
            } else if (stringOrArray == null) {
                results.add(null)
            } else {
                throw new RuntimeException(stringOrArray + " not a String or String[]");
            }
        }
        return result.toArray(new String[0]);
    }
    

    I could come up with a one liner (to avoid the method) but I don’t recommend it:

        foobar(1, new ArrayList<String>() {{
            addAll(Arrays.asList(arr1));
            addAll(Arrays.asList(arr2));
            add(arr3);
        }}.toArray(new String[0]));
    

    The only advantage the one-liner has is type safety.

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