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Home/ Questions/Q 4622058
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:47:24+00:00 2026-05-22T02:47:24+00:00

template <class T> class Singleton { public: static T& instance() { boost::call_once(init, flag); return

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template <class T>
class Singleton 
{
public:
  static T& instance()
  {
    boost::call_once(init, flag);
    return *t;
  }

  static void init()
  {
    t.reset(new T());
  }

protected:
  ~Singleton() {}
   Singleton() {}

private:
   static boost::scoped_ptr <T> t;
   static boost::once_flag flag;
};

template <class T> boost::scoped_ptr<T> Singleton<T>::t(0); 
template <class T> boost::once_flag Singleton<T>::flag = BOOST_ONCE_INIT; 

class TestClass : public Singleton<TestClass>
{
  friend class Singleton<TestClass>;
  private:
     TestClass(){}
};

For the above implemenation, I have a question below:

TestClass class1 = TestClass::instance();  
TestClass class2 = TestClass::instance();  

I found &class1 != &class2, is this a singleton?

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:47:25+00:00Added an answer on May 22, 2026 at 2:47 am
     TestClass class1 = TestClass::instance();
    

    You’re making a copy of the object returned by the factory, so you get a different object each time.

    To prevent this, get references to your singleton:

     TestClass& class1 = TestClass::instance();
    

    Still there is something strange because making a copy of MyClass issues compiler error (it inherit from boost::noncopyable via Singleton, so I’m not sure how you can compiled the code you posted.

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