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Home/ Questions/Q 6475385
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T06:41:54+00:00 2026-05-25T06:41:54+00:00

template <typename Z> Z myTemplate <Z> :: popFromVector () { if (myVector.empty () ==

  • 0
template <typename Z> Z myTemplate <Z> :: popFromVector ()
{
    if (myVector.empty () == false)
        return myVector.pop_back ();

    return 0;
}

int main ()
{
    myTemplate <int> obj;

    std :: cout << obj.popFromVector();

    return 0;
}

Error:

error: void value not ignored as it ought to be

AFAI can see, the return type of popFromVector is NOT void. What’s the point that I am missing?
The error disappears when I comment out this call in main().

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  1. Editorial Team
    Editorial Team
    2026-05-25T06:41:55+00:00Added an answer on May 25, 2026 at 6:41 am

    std::vector<T>::pop_back() returns void. You attempt to return it as an int. This is not allowed.

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