Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
template<class Y> operator auto_ptr_ref<Y>() throw() { return auto_ptr_ref<Y>(release()); } It is part of implementation of class auto_ptr in standard library.
What does this means to do?
Why there is an ‘auto_ptr_ref’ between ‘operator’ and ‘()’?
That is the conversion operator in action, casting from auto_ptr to auto_ptr_ref<Y>.