Question

The below prepared statement has 5 variables.

INSERT INTO folder (folder_name, folder_parent_id, folder_user_id, folder_order, hk_created) VALUES (?,?,?,?,?);

I’m getting this warning when I call $_STATEMENT->bind_result( $_RESULT );

Warning: mysqli_stmt::bind_result(): Number of bind variables doesn't match number of fields in prepared statement

While obviously this is true ( 5 variables, 1 result variable ) an INSERT statement when executed only returns true (success) or false (failure). Just in case there were something I were missing, I tried providing 5 variables to bind_result() and I still got the same message.

The Insert query executes successfully. Should I just @suppress the warning and chalk this up as either a quirk or bug in PHP (sometimes I wonder if there is a difference) or is there something I’m missing?

Edited to reflect that I tried giving 5 variables to bind_result()

Answer 1

You can’t use bind_result with an INSERT query. It doesn’t have a result.

$_STATEMENT->execute() will return TRUE or FALSE. Use $_STATEMENT->affected_rows if you want to see how many rows were inserted.