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Home/ Questions/Q 6876613
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:29:57+00:00 2026-05-27T04:29:57+00:00

The code below compiles well int a=5,b=4,c; a>b?30:40; Also does, int a=5,b=4,c; a>b?c=30:40; But

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The code below compiles well

int a=5,b=4,c;
a>b?30:40;

Also does,

int a=5,b=4,c;
a>b?c=30:40;

But why this does not work?

int a=5,b=4,c;
a>b?c=30:c=40;
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  1. Editorial Team
    Editorial Team
    2026-05-27T04:29:58+00:00Added an answer on May 27, 2026 at 4:29 am

    You are being bitten by precedence. ?: has very low precedence, but not as low as = or , (see the operator precedence table).

    Your code is parsed as:

    (a>b ? c=30 : c) = 40;
    

    Rather than:

    a>b ? c=30 : (c=40);
    

    You don’t need parenthesis around c=30 because ? and : act like parentheses to the expression within.


    Believe it or not, (a>b ? c=30 : c) = 40 is valid C++ (but not valid C). The expression (a>b ? c=30 : c) is an lvalue referencing the variable c, to which 40 is assigned.

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