Question

The first 3 bytes of a byte array are just integers, is there a better way to convert them? So far I have this but it just feels like a bad way of doing it.

public int parse_code(byte[] bs) {
    char[] array = new char[3];
    for(int i = 0; i < 3; i++) {
        array[i] = (char) bs[i];
    }

    // Dirty way of doing it
    return Integer.parseInt(new String(array));
}

Answer 1

If you know that there will always be 3 decimal digits at the beginning of the byte array you can just convert them into a integer directly:

public int parse_code( byte[] bs )
{
    int intval = 0;
    for( int i = 0; i < 3; i++ )
        intval = intval * 10 + ( bs[ i ] - '0' );
    return intval;
}