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Home/ Questions/Q 7438649
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T10:35:15+00:00 2026-05-29T10:35:15+00:00

The following code below launches a float-in div when my webpage loads, however I

  • 0

The following code below launches a float-in div when my webpage loads, however I need it to have a 60 second delay before it launches. Can anyone help? You can see a demo of the float-in div on http://www.bizassist.co.za.

Thank you.

Code:

var timer;
var h = -450;   
var w = 500;    
var t = 150;

function startAp() {
    setLeft();
    showAp();
}

function hideAp() { 
    if (document.layers) {
        document.layers.pa.visibility = 'hide';
    } else if (document.all) {
        document.all.pa.style.visibility = 'hidden';
    } else if (document.getElementById) {     
        document.getElementById("pa").style.visibility = 'hidden';
    }
}

function showAp() { 
    state=typeof tPos;

    if(state=='undefined') {
        tPos = h;
    }

    if(tPos < t) { 
        tPos+=25;
        if (document.layers) {
            document.layers.pa.top = tPos+"px";
        } else if (document.all) {
            document.all.pa.style.top = tPos+"px";
        } else if (document.getElementById) { 
            document.getElementById("pa").style.top = tPos+"px";
        }
    }

    if(timer!=null) clearInterval(timer);
    timer = setTimeout("showAp()",30);
}

function getoPos() {
    if (document.layers) {
        alert(document.layers.pa.top);
    } else if (document.all) {
        alert(document.all.pa.style.top);
    } else if (document.getElementById) { 
        alert(document.getElementById("pa").style.top);
    }
}

function setLeft() {
    if (document.layers) { 
        document.layers.pa.left = ((window.innerWidth / 2) - (w / 2))+"px";
    } else if (document.all) { 
        document.all.pa.style.left = ((document.body.offsetWidth / 2) - (w / 2))+"px";
    } else if (document.getElementById) {
        document.getElementById("pa").style.left = ((window.innerWidth / 2) - (w / 2)) + "px";
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T10:35:16+00:00Added an answer on May 29, 2026 at 10:35 am

    Use the setTimeout funcion to execute a function after some delay. Eg

    setTimout(showApp, 6000) // time is in milliseconds
    
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