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Home/ Questions/Q 6731495
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:32:10+00:00 2026-05-26T10:32:10+00:00

The following code prints *1. What’s mystifying is if I remove the comment it

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The following code prints “*1”. What’s mystifying is if I remove the comment it returns “*4” which is what I was expecting

var max = 0
lazy val list: Stream[Int] = 1 #:: Stream.from(2)
list.takeWhile {
  x =>
    max = x
    x < 4
}//.foreach(println)
println("*" + max)
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  1. Editorial Team
    Editorial Team
    2026-05-26T10:32:10+00:00Added an answer on May 26, 2026 at 10:32 am

    First of all: the lazy in your second line isn’t doing anything—you can remove it and get the same result.

    More importantly: takeWhile is actually lazy, in that it just returns another Stream, and nothing past the head of that stream will be evaluated until it’s needed. Consider the following:

    val s = Stream.from(1).takeWhile(_ > 0)
    

    You and I know that s is going to be an infinite stream, but if we fire up the REPL and type this in, it’s perfectly happy to evaluate it:

    scala> val s = Stream.from(1).takeWhile(_ > 0)
    s: scala.collection.immutable.Stream[Int] = Stream(1, ?)
    

    The same thing is happening in your example: the (Int) ⇒ Boolean that you’ve passed to takeWhile isn’t going to get fed any elements beyond the head of the stream, until something like your foreach makes that necessary.

    You can see this even more dramatically by adding something like a println inside of the takeWhile predicate:

    scala> val s = Stream.from(1).takeWhile { x => println("Checking: " + x); x < 4 }
    Checking: 1
    s: scala.collection.immutable.Stream[Int] = Stream(1, ?)
    
    scala> val l = s.toList
    Checking: 2
    Checking: 3
    Checking: 4
    l: List[Int] = List(1, 2, 3)
    

    Clearly the predicate only gets called for the head of the stream, until we force the evaluation of the rest of the stream by calling toList.

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