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Home/ Questions/Q 7883155
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T04:27:32+00:00 2026-06-03T04:27:32+00:00

The following code: var things = {‘foo’:’bar’} for ( thing in things ) {

  • 0

The following code:

var things = {'foo':'bar'}
for ( thing in things ) {
  console.log(thing)
}

Consistently produces the following error in jshint:

Bad for in variable 'thing'.

I do not understand what makes the ‘thing’ variable ‘bad’ – as you can see, it is not being used anywhere else. What should I do differently to make jshint not consider this to be an error?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T04:27:33+00:00Added an answer on June 3, 2026 at 4:27 am

    They always are – if they are not declared. Try adding var if thing has not been previously declared.

    for ( var thing in things ) {
      console.log(thing)
    }
    

    or

    var thing;
    
    //more code
    
    for ( thing in things ) {
      console.log(thing)
    }
    
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