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Home/ Questions/Q 8929707
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T08:43:49+00:00 2026-06-15T08:43:49+00:00

The following code will produce an assertion error def foo(a,b,c=’awesome’,d=null) { assert d }

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The following code will produce an assertion error

def foo(a,b,c='awesome',d=null) {
    assert d
}

foo(1,2,d='bar')

Why does it give an error? Why is the keyword assignment of d not working? I find this very different from Python keyword argument.

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  1. Editorial Team
    Editorial Team
    2026-06-15T08:43:50+00:00Added an answer on June 15, 2026 at 8:43 am

    Groovy doesn’t do keyword arguments quite the same as python.

    First, the syntax is map-like. Instead of

    foo(1,2,d='bar')
    

    you need

    foo(1,2,d:'bar')
    

    Second, groovy can’t map the arguments to keywords by name. A way to accomplish this in groovy is to accept the keyword arguments as a map:

    def foo(Map kwargs, a, b, c='awesome') { [a,b,c,kwargs.d] }
    assert foo(1,2,d:'bar') == [1,2,'awesome','bar']
    

    More details on how groovy handles this is here: http://groovy.codehaus.org/Extended+Guide+to+Method+Signatures.

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