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Home/ Questions/Q 861073
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T08:55:11+00:00 2026-05-15T08:55:11+00:00

The following test code (F#) is not returning the result I’d expect: let safeCount()

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The following test code (F#) is not returning the result I’d expect:

let safeCount() =
  let n = 1000000
  let counter = ref 0
  let spinlock = ref <| SpinLock(false)
  let run i0 i1 () =
    for i=i0 to i1-1 do
      let locked = ref false
      try
        (!spinlock).Enter locked
        if !locked then
          counter := !counter + 1
      finally
        if !locked then
          (!spinlock).Exit()
  let thread = System.Threading.Thread(run 0 (n/2))
  thread.Start()
  run (n/2) n ()
  thread.Join()
  !counter

I’d expect the SpinLock to mutually exclude the counter and, therefore, for it to return counts of 1,000,000 but, instead, it returns smaller values as if no mutual exclusion is occurring.

Any ideas what’s wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T08:55:11+00:00Added an answer on May 15, 2026 at 8:55 am

    EDIT:
    Stephen Swensen has a way to directly access a ref style SpinLock below. ! returns a copy of structs so should not be used in this case.

    You can wrap SpinLock in a class it works (I tried using a static and immutable SpinLock to no avail)

    type SpinLockClass() =
        let s = System.Threading.SpinLock(false)
        member x.Enter locked = s.Enter(locked)
        member x.Exit() = s.Exit()
    
    let safeCount() =
      let n = 1000000
      let counter = ref 0
      let spinlock = SpinLockClass()
      let run i0 i1 () =
        for i=i0 to i1-1 do
          let locked = ref false
          try
            spinlock.Enter locked
            if !locked then
              counter := !counter + 1
          finally
            if !locked then
              spinlock.Exit()
      let thread = System.Threading.Thread(run 0 (n/2))
      thread.Start()
      run (n/2) n ()
      thread.Join()
      !counter
    
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