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Home/ Questions/Q 993585
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T06:26:49+00:00 2026-05-16T06:26:49+00:00

The following (test with gcc -E blah.c ): #define UNUSED(type) type UNUSED_ ## __COUNTER__

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The following (test with gcc -E blah.c):

#define UNUSED(type) type UNUSED_ ## __COUNTER__
UNUSED(char const *)
UNUSED(int)

Generates:

char const * UNUSED__COUNTER__
int UNUSED__COUNTER__

I’m expecting:

char const * UNUSED0
int UNUSED1

I’ve tried calling another macro, wrapping the arguments in brackets to no avail.
If I don’t paste the tokens it seems to work fine.
The documentation specifically mentions the use of __COUNTER__ in token pasting.

What am I doing wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-16T06:26:50+00:00Added an answer on May 16, 2026 at 6:26 am

    Experimenting with gcc 4.4, this works:

    #define UNUSED(type) UNUSED_(type, __COUNTER__)
    #define UNUSED_(type, counter) UNUSED__(type, counter)
    #define UNUSED__(type, counter) type UNUSED_ ## counter
    UNUSED(char const *)
    UNUSED(int)
    

    But it doesn’t work if I take out even one level of intermediates.

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