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Home/ Questions/Q 8256093
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T01:44:36+00:00 2026-06-08T01:44:36+00:00

The haskell code below compiles, Ok. data Point = Point Float Float data Radius

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The haskell code below compiles, Ok.

data Point = Point Float Float  
data Radius = Radius Float  
data Shape = Circle Point Radius

Is it possible to write something in line with the code below (Code fails compiling):

data LengthQty = Radius Float | Length Float | Width Float   
data Shape = Circle Point Radius

Idea behind this attempt is that Radius, Length and Width are representing Physical Quantity Length.

Please note that in the second part second line if written like

data Shape = Circle Point LengthQty

Then, it compiles, but in that case the “LengthQty” can be anything like Length, Width or Radius, where only Radius is required.

(1) What is wrong in second part?
(2) How it can be corrected to implement the idea of Physical Quantity Length (LengthQty)?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T01:44:39+00:00Added an answer on June 8, 2026 at 1:44 am

    The reason that your code doesn’t compile is that the right-hand side of a data declaration must be a constructor followed by a list of types, i.e. of the form

    data {-type-} = {-constructor-} {-type-} ... {-type-}
    

    In your example, when you define

    data LengthQty = Radius Float | Length Float | Width Float 
    

    you have made LengthQty a type whereas Radius, Length and Width are constructors. Therefore when you write

    data Shape = Circle Point Radius
    

    the compiler sees something of the form

    data {-type-} = {-constructor-} {-type-} {-constructor-}
    

    i.e. it sees a constructor where it is expecting a type, so it throws an error. In the original code, the symbol Radius was used for both a constructor and a type. When the compiler sees

    data Shape = Circle Point Radius
    

    it knows that Radius in this context has to be a type, so there is no possibility of confusion with the constructor radius.

    With this in mind, you can make your code compile correctly if you just write

    data Shape = Circle Point LengthQty
    

    and you can get a particular instance of a circle with

    circle :: Shape
    circle = Circle (Point 0 0) (Radius 1)
    
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