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Home/ Questions/Q 3339948
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T00:33:04+00:00 2026-05-18T00:33:04+00:00

The standard way to create an object in Objective-C looks like this: MyClass* object

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The standard way to create an object in Objective-C looks like this:

MyClass* object = [[MyClass alloc] init];

The standard implementation of MyClass‘s init method would look something like this:

-(id) init
{
    self = [super init];
    if(self) { /* initialize */ }
    return self;
}

Aside from some syntax changes, and excluding factory methods, that seems to be the recommended way to write an init method, and to use it.

As I understand it, the purpose of self = [super init]; is to handle the case where [super init] fails. But if it does fail, and returns nil, wouldn’t there be a memory leak? The reason being that MyClass‘s init will return nil, object will be nil, there will be no more pointers that reference the object allocated with [MyClass alloc], and therefore no way to release it.

These are the two solutions I can think of are, but I haven’t seen either one in regular practice.

After a call to alloc, check the results before calling init:

MyClass* object = [MyClass alloc];
if(object == nil) { /*handle the error */ }
else { object = [object init]; }

Or, if [super init] fails, release the memory. Something like this:

-(id) init
{
    id temp = [super init];
    if(!temp) { [self release]; }
    self = temp;
    if(self) { /* initialize */ }
    return self;
}

Am I wrong in that reasoning? It could be argued that [super init] is unlikely to fail, but then why assign the results of it to self and check for nil? I’d be happy to see some clarification.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T00:33:04+00:00Added an answer on May 18, 2026 at 12:33 am

    If [super init] wants to return nil, it should also call release on self.

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