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Home/ Questions/Q 1958130
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T07:59:24+00:00 2026-05-17T07:59:24+00:00

the subject basically sums it up, but i am working on a calendar in

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the subject basically sums it up, but i am working on a calendar in php for a client that should pull events from a table and display them in the appropriate cells.

the calendar table is working no prob, but what i am trying to avoid is making a separate DB call for each day of the month.

i am trying to figure out a way to store the results in an array of arrays first, then as the calendar is created, each day that has an event(s) would display some portion of the data for that even there.

it’s a conceptual problem i am having and i can’t seem to solve it.

also, not sure if it’s possible.

any help is appreciated.

thanks.

for example:

select day, title, desc where month = $month and year = $year order by day asc

and ultimately output something like this without hitting the DB 31 times:

day1.
title / desc


day2.
title / desc <br>
title / desc


day3. 
title / desc
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  1. Editorial Team
    Editorial Team
    2026-05-17T07:59:28+00:00Added an answer on May 17, 2026 at 7:59 am

    you can do one query to get all the events in this mounth,

    like you write

     select day, title, desc from mytable 
    where month = $month and year = $year order by day asc
    

    and in the foreach loop on the results,
    store it in array like

    while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
        $events[$row['day']][] = $row;
    }
    

    so in the end of the loop you have array $events, where every entry contain an array of the events in this day.

    like $events[1], $events[2] ....

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