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Editorial Team
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Asked: 2026-05-27T00:21:34+00:00

The table is currently this: CREATE TABLE `feed_items` ( `id` int(11) unsigned NOT NULL

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The table is currently this:

CREATE TABLE `feed_items` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `feed_id` int(11) NOT NULL,
  `remote_id` varchar(32) NOT NULL DEFAULT '',
  `title` varchar(255) NOT NULL DEFAULT '',
  `link` varchar(255) NOT NULL DEFAULT '',
  `updated_time` datetime NOT NULL,
  `created_time` datetime NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;

I need to find a way so that if i pull multiple RSS feeds into one table, and articles with the same Title have the same value of ‘remote_id’, how can i make sure I do not insert a duplicate value?

I am currently using 

$this->db->query('INSERT INTO feed_items(feed_id, remote_id, link, title, created_time, updated_time) VALUES (?, ?, ?, ?, ?, NOW()) ON DUPLICATE KEY UPDATE remote_id=remote_id', array($this->feed_id, $this->remote_id, $this->link, $this->title, $this->created_time, $this->remote_id));

I was wondering if there is a better way?

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1 Answer

  1. Editorial Team

    Thanks for the replies!

    I actually managed to solve it a few hours after posting this, I made the remote_id a unique column and then did the following for the SQL

    INSERT INTO feed_items(feed_id, remote_id, link, title, created_time, updated_time) VALUES (?, ?, ?, ?, ?, NOW()) ON DUPLICATE KEY UPDATE remote_id=remote_id
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