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Home/ Questions/Q 7888967
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T05:58:28+00:00 2026-06-03T05:58:28+00:00

The thread will enter the synchronized code only when the condition uniqueInstance == null

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The thread will enter the synchronized code only when the condition uniqueInstance == null sets to true, so what is the need to check it again inside the critical section?

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  1. Editorial Team
    Editorial Team
    2026-06-03T05:58:29+00:00Added an answer on June 3, 2026 at 5:58 am

    Because in between the check and the synchronized call you could have been interrupted by another process which acquired the semaphore, wrote to the singleton, and quit. There’s a possibility that you’ll overwrite the value that the other process already initialized unless you check again.

    On the other hand, if you make the whole method synchronized, you pay the cost of synchronization on every call to the singleton rather than the first call only. It’s better to check twice.

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