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Home/ Questions/Q 8918565
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T05:47:15+00:00 2026-06-15T05:47:15+00:00

There is a list of String [f, 1, h, 6, b, 7]. How can

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There is a list of String [“f”, “1”, “h”, “6”, “b”, “7”].

How can I count Int in this list?

Now I have this algorithm but it’s not so good.

import Data.Char
let listOfStrings = ["f", "1", "h", "6", "b", "7"]
let convertedString = "f1h6b7"
let listOfInt = map (\x -> read [x]::Int) (filter (\x -> isDigit x) convertedString)
length listOfInt
Prelude> 3

Besides, I can’t convert listOfStrings to one string. This algorithm doesn’t even work properly

Can you help me with optimization?

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  1. Editorial Team
    Editorial Team
    2026-06-15T05:47:17+00:00Added an answer on June 15, 2026 at 5:47 am

    1) Use reads :: Reads Int (this expression is just reads :: String -> [(Int, String)] in disguise) to test whether a string is a representation of an integer value:

    isNumber :: String -> Bool
    isNumber s = case (reads s) :: [(Int, String)] of
        [(_, "")] -> True
        _         -> False
    

    Why reads? Because it returns additional information about parsing process from which we can conclude if it was successful. read :: Int would just throw an exception.

    2) then filter a list of strings with it and take its length:

    intsCount :: [String] -> Int 
    intsCount = length . filter isNumber
    
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