Question

There is list

<nodes>
<node attr='1'/>
<node attr='0'/>
<node attr='1'/>
<node attr='1'/>
</nodes>

i need to apply-templates all nodes and count it:

<xsl:apply-templates select='nodes/node'>
<xsl:if test='@attr=1'>
<xsl:number/>
</xsl:if>
</xsl:apply-templates>

but a haz in result not 123, result is 134. How to fix it in xslt-1.0? There is another way to set numbers to it? position() not help, and

<xsl:apply-templates select='nodes/node[@attr=1]'>
<xsl:if test='@attr=1'>
<xsl:number/>
</xsl:if>
</xsl:apply-templates>

not help to =(((

Answer 1

Firstly, you have an error in your XSLT

<xsl:apply-templates select='nodes/node'> 
   <xsl:if test='@attr=1'> <xsl:number/>     
   </xsl:if>
</xsl:apply-templates> 

You can’t have an xsl:if within an xsl:apply-templates. You need a matching xsl:template and put the code in there…

<xsl:apply-templates select="nodes/node" />

<xsl:template match="node">
   <xsl:if test='@attr=1'>
      <xsl:number/>     
   </xsl:if>
<xsl:template> 

In fact, you could do away with the xsl:if here, and just have the test in the template match

<xsl:template match="node[@attr=1]">
    <xsl:number/>     
<xsl:template> 

But to answer your question, you probably need to use the count attribute on the xsl:number element to count only the elements you want

<xsl:number count="node[@attr=1]"/>

Here is the full XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output method="xml" indent="yes"/>

   <xsl:template match="/">
      <xsl:apply-templates select="nodes/node"/>
   </xsl:template>

   <xsl:template match="node[@attr=1]">
      <xsl:number count="node[@attr=1]"/>
   </xsl:template>

   <xsl:template match="node"/>
</xsl:stylesheet>

When applied to you XML, the result is 123