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Home/ Questions/Q 6955739
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:46:36+00:00 2026-05-27T14:46:36+00:00

There is this code: #include <iostream> class SomeClass { int someInteger; float someFloat; public:

  • 0

There is this code:

#include <iostream>
class SomeClass
{
  int someInteger;
  float someFloat;
public:
  SomeClass(int someInteger_)
  {
    // do something for int
    std::cout << "Int constructor\n";
  }
  SomeClass(float someFloat_)
  {
    // do something for float
    std::cout << "Float constructor\n";
  }
};

int main()
{
  SomeClass a(2);
  SomeClass b(2.0f);
  return 0;
}

Objects of class SomeClass are differently created when float or int arguments for constructors are passed. There is similar class in Python:

class SomeClass:
    someInteger = 0
    someFloat = 0.0
    def __init__(self, value):
        # I want to do different things when int or float is passed
        print value

a = SomeClass(2)
b = SomeClass(2.0)

General question is – how to make function behavior dependent from types of passed arguments?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:46:36+00:00Added an answer on May 27, 2026 at 2:46 pm

    Use isinstance:

    >>> isinstance(1, int)
    True
    >>> isinstance(1, float)
    False
    >>> isinstance(1.1, float)
    True
    >>> isinstance(1.1, int)
    False
    

    Or for you constructor:

    def __init__(self, value):
        if isinstance(value, int):
            # int constructor
        elif isinstance(value, float):
            # float constructor
        else:
            raise TypeError, 'Unexpected type'
    
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