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Home/ Questions/Q 7443967
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T11:25:01+00:00 2026-05-29T11:25:01+00:00

There is this code: #include <iostream> template<const double& f> void fun5(){ std::cout << f

  • 0

There is this code:

#include <iostream>

template<const double& f>
void fun5(){
    std::cout << f << std::endl;
} 

//const double dddd = 5.0; error: ‘dddd’ cannot appear in a constant-expression
//however it works for extern const double dddd = 5.0;

double dddd = 5.0; // works

int main() 
{ 
    fun5<dddd>();
    return 0;
} 

const double dddd doesn’t work as template parameter (however extern const double dddd works). double dddd works, but it is not constant. What is difference between extern const double and const double variables defined in global scope?

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  1. Editorial Team
    Editorial Team
    2026-05-29T11:25:01+00:00Added an answer on May 29, 2026 at 11:25 am

    const gives variables internal linkage by default, while both extern and non-const do not. Internal linkage symbols are expressly prohibited from being template parameters by the standard (pre-C++11, I know a few things changed there).

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